1. Rewrite the reaction equations, the schemes of which are given below: a)Ba → BaO → Ba(OH)2 → Ba(NO3), - BaSO4Al

Решим задачу по частям, чтобы ответ был максимально подробным и понятным.

a) Ba → BaO → Ba(OH)2 → Ba(NO3)

- Re-acting the metal Ba with oxygen (O2) yields Barium Oxide (BaO). The equation can be written as:
\[2Ba+O_2 \rightarrow 2BaO\]

- Adding water (H2O) to Barium Oxide results in Barium Hydroxide (Ba(OH)2). The balanced equation is:
\[BaO+H_2O \rightarrow Ba(OH)_2\]

- Lastly, reacting Barium Hydroxide with Nitric Acid (HNO3) produces Barium Nitrate (Ba(NO3)2). The balanced equation is:
\[Ba(OH)_2+2HNO_3 \rightarrow Ba(NO_3)_2+2H_2O\]

b) Fe → FeO → FeCl2 → Fe(OH)2 → FeO → FeSO4

- The reaction between Iron (Fe) and Oxygen (O2) gives Iron(II) Oxide (FeO). The balanced equation is:
\[4Fe+O_2 \rightarrow 2Fe_2O_3\]
Here, FeO can be considered an intermediate product.

- Adding Hydrochloric Acid (HCl) to the Iron(II) Oxide gives Iron(II) Chloride (FeCl2). The equation can be written as:
\[FeO+2HCl \rightarrow FeCl_2+H_2O\]

- Reacting Iron(II) Chloride with Water (H2O) produces Iron(II) Hydroxide (Fe(OH)2). The balanced equation is:
\[FeCl_2+2H_2O \rightarrow Fe(OH)_2+2HCl\]

- Heating Iron(II) Hydroxide yields back Iron(II) Oxide. The equation is:
\[Fe(OH)_2 \rightarrow FeO+H_2O\]

- Finally, reacting Iron(II) Oxide with Sulfuric Acid (H2SO4) results in Iron(II) Sulfate (FeSO4). The balanced equation is:
\[FeO+H_2SO_4 \rightarrow FeSO_4+H_2O\]

c) C → CO2 → H2CO3 → CaCO3 → CaO → CaCl2

- The combustion of Carbon (C) with Oxygen (O2) gives Carbon Dioxide (CO2). The balanced equation is:
\[C+O_2 \rightarrow CO_2\]

- Dissolving Carbon Dioxide into water produces Carbonic Acid (H2CO3). The equation can be written as:
\[CO_2+H_2O \rightarrow H_2CO_3\]

- Reacting Carbonic Acid with Calcium Carbonate (CaCO3) yields Calcium Hydrogen Carbonate (Ca(HCO3)2). The balanced equation is:
\[H_2CO_3+CaCO_3 \rightarrow Ca(HCO_3)_2\]

- Heating Calcium Hydrogen Carbonate leaves behind Calcium Oxide (CaO) and Water (H2O). The equation is:
\[Ca(HCO_3)_2 \rightarrow CaO+H_2O+2CO_2\]

- Finally, Calcium Oxide reacts with Hydrochloric Acid (HCl) to produce Calcium Chloride (CaCl2). The balanced equation is:
\[CaO+2HCl \rightarrow CaCl_2+H_2O\]

d) P → P2O5 → H3PO4 → Ca3(PO4)2 → H3PO4 → Ca(H2PO4)2

- The reaction between Phosphorus (P4) and Oxygen (O2) gives Phosphorus Pentoxide (P2O5). The balanced equation is:
\[P4+5O_2 \rightarrow 2P_2O_5\]

- Dissolving Phosphorus Pentoxide in water produces Phosphoric Acid (H3PO4). The equation can be written as:
\[P_2O_5+3H_2O \rightarrow 2H_3PO_4\]

- Reacting Phosphoric Acid with Calcium Hydroxide (Ca(OH)2) yields Calcium Phosphate (Ca3(PO4)2) and Water (H2O). The balanced equation is:
\[2H_3PO_4+3Ca(OH)_2 \rightarrow Ca_3(PO_4)_2+6H_2O\]

- Treating Calcium Phosphate with Concentrated Phosphoric Acid results in the regeneration of Phosphoric Acid. The equation can be written as:
\[Ca_3(PO_4)_2+4H_3PO_4 \rightarrow 3Ca(H_2PO_4)_2\]

- Finally, Calcium Hydrogen Phosphate (Ca(H2PO4)2) is formed when Phosphoric Acid reacts with Calcium Carbonate (CaCO3). The balanced equation is:
\[3Ca(H_2PO_4)_2+CaCO_3→ 3Ca(H_2PO_4)_2+CO_2+H_2O\]

Надеюсь, объяснение помогло вам понять продукты реакции в каждом случае.